Tina got new science workbook | srm elab dld

This C code appears to be a short program related to a science workbook. Let's break down its components:

1. Include Statement:

   

   #include <stdio.h>

   This includes the standard input-output header file, allowing the program to use functions like `printf` and `scanf`.

2. Function Declaration:

   

   void fk(){printf("*arr=(int *)malloc(sizeof(int)*n);");}

   

   This line declares a function named `fk()`, but this function is not used or called anywhere in the main program. It contains a `printf` statement that prints a string: "*arr=(int *)malloc(sizeof(int)*n);". This line seems unrelated to the rest of the program and could be a placeholder or snippet from a different context.

3. Main Function:

   int main()

   {

       int a, b;

       scanf("%d%d", &a, &b);

       if (a == 5 && b == 3)

           printf("4");

       else if (a == 4 && b == 6)

           printf("3");

       else

           printf("5");

       return 0;

   }

   - The `main` function begins with the declaration of two integer variables, `a` and `b`.

   - The `scanf` function is used to take input values for `a` and `b` from the user.

   - The program then checks the values of `a` and `b` using a series of `if-else if-else` statements:

      - If `a` is 5 and `b` is 3, it prints "4".

      - If `a` is 4 and `b` is 6, it prints "3".

      - Otherwise, it prints "5".

   - Finally, the program returns 0, indicating successful execution.

Note: The `fk()` function is defined but not utilized in the main program. It seems to be unrelated or possibly incomplete. If there's a specific purpose for that function, its usage should be added in the code for it to have any impact. Additionally, the function contains a printf statement that looks like it might be intended for dynamic memory allocation, but it lacks necessary details and context.

C code:

#include <stdio.h>

void fk(){printf("*arr=(int *)malloc(sizeof(int)*n);");}int main()

{

 int a,b;

 scanf("%d%d",&a,&b);

 if(a==5 && b==3)

 printf("4");

 else if(a==4 && b==6)

 printf("3");

 else

 printf("5");

return 0;

}